3.1.46 \(\int \csc ^7(c+d x) (a+a \sec (c+d x))^3 \, dx\) [46]

3.1.46.1 Optimal result
3.1.46.2 Mathematica [A] (verified)
3.1.46.3 Rubi [A] (verified)
3.1.46.4 Maple [A] (verified)
3.1.46.5 Fricas [B] (verification not implemented)
3.1.46.6 Sympy [F(-1)]
3.1.46.7 Maxima [A] (verification not implemented)
3.1.46.8 Giac [A] (verification not implemented)
3.1.46.9 Mupad [B] (verification not implemented)

3.1.46.1 Optimal result

Integrand size = 21, antiderivative size = 157 \[ \int \csc ^7(c+d x) (a+a \sec (c+d x))^3 \, dx=-\frac {a^6}{6 d (a-a \cos (c+d x))^3}-\frac {7 a^5}{8 d (a-a \cos (c+d x))^2}-\frac {31 a^4}{8 d (a-a \cos (c+d x))}+\frac {111 a^3 \log (1-\cos (c+d x))}{16 d}-\frac {7 a^3 \log (\cos (c+d x))}{d}+\frac {a^3 \log (1+\cos (c+d x))}{16 d}+\frac {3 a^3 \sec (c+d x)}{d}+\frac {a^3 \sec ^2(c+d x)}{2 d} \]

output
-1/6*a^6/d/(a-a*cos(d*x+c))^3-7/8*a^5/d/(a-a*cos(d*x+c))^2-31/8*a^4/d/(a-a 
*cos(d*x+c))+111/16*a^3*ln(1-cos(d*x+c))/d-7*a^3*ln(cos(d*x+c))/d+1/16*a^3 
*ln(1+cos(d*x+c))/d+3*a^3*sec(d*x+c)/d+1/2*a^3*sec(d*x+c)^2/d
 
3.1.46.2 Mathematica [A] (verified)

Time = 0.78 (sec) , antiderivative size = 129, normalized size of antiderivative = 0.82 \[ \int \csc ^7(c+d x) (a+a \sec (c+d x))^3 \, dx=-\frac {a^3 (1+\cos (c+d x))^3 \sec ^6\left (\frac {1}{2} (c+d x)\right ) \left (186 \csc ^2\left (\frac {1}{2} (c+d x)\right )+21 \csc ^4\left (\frac {1}{2} (c+d x)\right )+2 \csc ^6\left (\frac {1}{2} (c+d x)\right )-12 \left (\log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )-56 \log (\cos (c+d x))+111 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )+24 \sec (c+d x)+4 \sec ^2(c+d x)\right )\right )}{768 d} \]

input
Integrate[Csc[c + d*x]^7*(a + a*Sec[c + d*x])^3,x]
 
output
-1/768*(a^3*(1 + Cos[c + d*x])^3*Sec[(c + d*x)/2]^6*(186*Csc[(c + d*x)/2]^ 
2 + 21*Csc[(c + d*x)/2]^4 + 2*Csc[(c + d*x)/2]^6 - 12*(Log[Cos[(c + d*x)/2 
]] - 56*Log[Cos[c + d*x]] + 111*Log[Sin[(c + d*x)/2]] + 24*Sec[c + d*x] + 
4*Sec[c + d*x]^2)))/d
 
3.1.46.3 Rubi [A] (verified)

Time = 0.47 (sec) , antiderivative size = 146, normalized size of antiderivative = 0.93, number of steps used = 12, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.524, Rules used = {3042, 4360, 25, 25, 3042, 25, 3315, 25, 27, 99, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \csc ^7(c+d x) (a \sec (c+d x)+a)^3 \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {\left (a-a \csc \left (c+d x-\frac {\pi }{2}\right )\right )^3}{\cos \left (c+d x-\frac {\pi }{2}\right )^7}dx\)

\(\Big \downarrow \) 4360

\(\displaystyle \int \csc ^7(c+d x) \sec ^3(c+d x) \left (-(a (-\cos (c+d x))-a)^3\right )dx\)

\(\Big \downarrow \) 25

\(\displaystyle -\int -(\cos (c+d x) a+a)^3 \csc ^7(c+d x) \sec ^3(c+d x)dx\)

\(\Big \downarrow \) 25

\(\displaystyle \int \csc ^7(c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int -\frac {\left (a-a \sin \left (c+d x-\frac {\pi }{2}\right )\right )^3}{\sin \left (c+d x-\frac {\pi }{2}\right )^3 \cos \left (c+d x-\frac {\pi }{2}\right )^7}dx\)

\(\Big \downarrow \) 25

\(\displaystyle -\int \frac {\left (a-a \sin \left (\frac {1}{2} (2 c-\pi )+d x\right )\right )^3}{\cos \left (\frac {1}{2} (2 c-\pi )+d x\right )^7 \sin \left (\frac {1}{2} (2 c-\pi )+d x\right )^3}dx\)

\(\Big \downarrow \) 3315

\(\displaystyle \frac {a^7 \int -\frac {\sec ^3(c+d x)}{(a-a \cos (c+d x))^4 (\cos (c+d x) a+a)}d(a \cos (c+d x))}{d}\)

\(\Big \downarrow \) 25

\(\displaystyle -\frac {a^7 \int \frac {\sec ^3(c+d x)}{(a-a \cos (c+d x))^4 (\cos (c+d x) a+a)}d(a \cos (c+d x))}{d}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {a^{10} \int \frac {\sec ^3(c+d x)}{a^3 (a-a \cos (c+d x))^4 (\cos (c+d x) a+a)}d(a \cos (c+d x))}{d}\)

\(\Big \downarrow \) 99

\(\displaystyle -\frac {a^{10} \int \left (\frac {\sec ^3(c+d x)}{a^8}+\frac {3 \sec ^2(c+d x)}{a^8}+\frac {7 \sec (c+d x)}{a^8}+\frac {111}{16 a^7 (a-a \cos (c+d x))}-\frac {1}{16 a^7 (\cos (c+d x) a+a)}+\frac {31}{8 a^6 (a-a \cos (c+d x))^2}+\frac {7}{4 a^5 (a-a \cos (c+d x))^3}+\frac {1}{2 a^4 (a-a \cos (c+d x))^4}\right )d(a \cos (c+d x))}{d}\)

\(\Big \downarrow \) 2009

\(\displaystyle -\frac {a^{10} \left (-\frac {\sec ^2(c+d x)}{2 a^7}-\frac {3 \sec (c+d x)}{a^7}+\frac {7 \log (a \cos (c+d x))}{a^7}-\frac {111 \log (a-a \cos (c+d x))}{16 a^7}-\frac {\log (a \cos (c+d x)+a)}{16 a^7}+\frac {31}{8 a^6 (a-a \cos (c+d x))}+\frac {7}{8 a^5 (a-a \cos (c+d x))^2}+\frac {1}{6 a^4 (a-a \cos (c+d x))^3}\right )}{d}\)

input
Int[Csc[c + d*x]^7*(a + a*Sec[c + d*x])^3,x]
 
output
-((a^10*(1/(6*a^4*(a - a*Cos[c + d*x])^3) + 7/(8*a^5*(a - a*Cos[c + d*x])^ 
2) + 31/(8*a^6*(a - a*Cos[c + d*x])) + (7*Log[a*Cos[c + d*x]])/a^7 - (111* 
Log[a - a*Cos[c + d*x]])/(16*a^7) - Log[a + a*Cos[c + d*x]]/(16*a^7) - (3* 
Sec[c + d*x])/a^7 - Sec[c + d*x]^2/(2*a^7)))/d)
 

3.1.46.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 99
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], 
 x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | 
| (GtQ[m, 0] && GeQ[n, -1]))
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3315
Int[cos[(e_.) + (f_.)*(x_)]^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_ 
.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> Simp[1/(b^p* 
f)   Subst[Int[(a + x)^(m + (p - 1)/2)*(a - x)^((p - 1)/2)*(c + (d/b)*x)^n, 
 x], x, b*Sin[e + f*x]], x] /; FreeQ[{a, b, e, f, c, d, m, n}, x] && Intege 
rQ[(p - 1)/2] && EqQ[a^2 - b^2, 0]
 

rule 4360
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_.)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + 
(a_))^(m_.), x_Symbol] :> Int[(g*Cos[e + f*x])^p*((b + a*Sin[e + f*x])^m/Si 
n[e + f*x]^m), x] /; FreeQ[{a, b, e, f, g, p}, x] && IntegerQ[m]
 
3.1.46.4 Maple [A] (verified)

Time = 1.12 (sec) , antiderivative size = 164, normalized size of antiderivative = 1.04

method result size
parallelrisch \(\frac {79 \left (\frac {112 \left (-\cos \left (2 d x +2 c \right )-1\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{79}+\frac {112 \left (-\cos \left (2 d x +2 c \right )-1\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{79}+\frac {222 \left (1+\cos \left (2 d x +2 c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{79}+\cot \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} \csc \left (\frac {d x}{2}+\frac {c}{2}\right )^{4} \left (\cos \left (d x +c \right )-\frac {161 \cos \left (2 d x +2 c \right )}{237}+\frac {71 \cos \left (3 d x +3 c \right )}{237}-\frac {449 \cos \left (4 d x +4 c \right )}{7584}-\frac {4319}{7584}\right )\right ) a^{3}}{16 d \left (1+\cos \left (2 d x +2 c \right )\right )}\) \(164\)
norman \(\frac {-\frac {a^{3}}{48 d}-\frac {23 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{96 d}-\frac {91 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{48 d}-\frac {103 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{8}}{16 d}+\frac {339 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}}{32 d}}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6} \left (-1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{2}}+\frac {111 a^{3} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d}-\frac {7 a^{3} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{d}-\frac {7 a^{3} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{d}\) \(172\)
risch \(\frac {a^{3} \left (165 \,{\mathrm e}^{9 i \left (d x +c \right )}-822 \,{\mathrm e}^{8 i \left (d x +c \right )}+1852 \,{\mathrm e}^{7 i \left (d x +c \right )}-2754 \,{\mathrm e}^{6 i \left (d x +c \right )}+3182 \,{\mathrm e}^{5 i \left (d x +c \right )}-2754 \,{\mathrm e}^{4 i \left (d x +c \right )}+1852 \,{\mathrm e}^{3 i \left (d x +c \right )}-822 \,{\mathrm e}^{2 i \left (d x +c \right )}+165 \,{\mathrm e}^{i \left (d x +c \right )}\right )}{12 d \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )^{6} \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{2}}+\frac {a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{8 d}+\frac {111 a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{8 d}-\frac {7 a^{3} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{d}\) \(196\)
derivativedivides \(\frac {a^{3} \left (-\frac {1}{6 \sin \left (d x +c \right )^{6} \cos \left (d x +c \right )^{2}}-\frac {1}{3 \sin \left (d x +c \right )^{4} \cos \left (d x +c \right )^{2}}+\frac {1}{\sin \left (d x +c \right )^{2} \cos \left (d x +c \right )^{2}}-\frac {2}{\sin \left (d x +c \right )^{2}}+4 \ln \left (\tan \left (d x +c \right )\right )\right )+3 a^{3} \left (-\frac {1}{6 \sin \left (d x +c \right )^{6} \cos \left (d x +c \right )}-\frac {7}{24 \sin \left (d x +c \right )^{4} \cos \left (d x +c \right )}-\frac {35}{48 \sin \left (d x +c \right )^{2} \cos \left (d x +c \right )}+\frac {35}{16 \cos \left (d x +c \right )}+\frac {35 \ln \left (-\cot \left (d x +c \right )+\csc \left (d x +c \right )\right )}{16}\right )+3 a^{3} \left (-\frac {1}{6 \sin \left (d x +c \right )^{6}}-\frac {1}{4 \sin \left (d x +c \right )^{4}}-\frac {1}{2 \sin \left (d x +c \right )^{2}}+\ln \left (\tan \left (d x +c \right )\right )\right )+a^{3} \left (\left (-\frac {\csc \left (d x +c \right )^{5}}{6}-\frac {5 \csc \left (d x +c \right )^{3}}{24}-\frac {5 \csc \left (d x +c \right )}{16}\right ) \cot \left (d x +c \right )+\frac {5 \ln \left (-\cot \left (d x +c \right )+\csc \left (d x +c \right )\right )}{16}\right )}{d}\) \(273\)
default \(\frac {a^{3} \left (-\frac {1}{6 \sin \left (d x +c \right )^{6} \cos \left (d x +c \right )^{2}}-\frac {1}{3 \sin \left (d x +c \right )^{4} \cos \left (d x +c \right )^{2}}+\frac {1}{\sin \left (d x +c \right )^{2} \cos \left (d x +c \right )^{2}}-\frac {2}{\sin \left (d x +c \right )^{2}}+4 \ln \left (\tan \left (d x +c \right )\right )\right )+3 a^{3} \left (-\frac {1}{6 \sin \left (d x +c \right )^{6} \cos \left (d x +c \right )}-\frac {7}{24 \sin \left (d x +c \right )^{4} \cos \left (d x +c \right )}-\frac {35}{48 \sin \left (d x +c \right )^{2} \cos \left (d x +c \right )}+\frac {35}{16 \cos \left (d x +c \right )}+\frac {35 \ln \left (-\cot \left (d x +c \right )+\csc \left (d x +c \right )\right )}{16}\right )+3 a^{3} \left (-\frac {1}{6 \sin \left (d x +c \right )^{6}}-\frac {1}{4 \sin \left (d x +c \right )^{4}}-\frac {1}{2 \sin \left (d x +c \right )^{2}}+\ln \left (\tan \left (d x +c \right )\right )\right )+a^{3} \left (\left (-\frac {\csc \left (d x +c \right )^{5}}{6}-\frac {5 \csc \left (d x +c \right )^{3}}{24}-\frac {5 \csc \left (d x +c \right )}{16}\right ) \cot \left (d x +c \right )+\frac {5 \ln \left (-\cot \left (d x +c \right )+\csc \left (d x +c \right )\right )}{16}\right )}{d}\) \(273\)

input
int(csc(d*x+c)^7*(a+a*sec(d*x+c))^3,x,method=_RETURNVERBOSE)
 
output
79/16*(112/79*(-cos(2*d*x+2*c)-1)*ln(tan(1/2*d*x+1/2*c)-1)+112/79*(-cos(2* 
d*x+2*c)-1)*ln(tan(1/2*d*x+1/2*c)+1)+222/79*(1+cos(2*d*x+2*c))*ln(tan(1/2* 
d*x+1/2*c))+cot(1/2*d*x+1/2*c)^2*csc(1/2*d*x+1/2*c)^4*(cos(d*x+c)-161/237* 
cos(2*d*x+2*c)+71/237*cos(3*d*x+3*c)-449/7584*cos(4*d*x+4*c)-4319/7584))*a 
^3/d/(1+cos(2*d*x+2*c))
 
3.1.46.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 297 vs. \(2 (148) = 296\).

Time = 0.28 (sec) , antiderivative size = 297, normalized size of antiderivative = 1.89 \[ \int \csc ^7(c+d x) (a+a \sec (c+d x))^3 \, dx=\frac {330 \, a^{3} \cos \left (d x + c\right )^{4} - 822 \, a^{3} \cos \left (d x + c\right )^{3} + 596 \, a^{3} \cos \left (d x + c\right )^{2} - 72 \, a^{3} \cos \left (d x + c\right ) - 24 \, a^{3} - 336 \, {\left (a^{3} \cos \left (d x + c\right )^{5} - 3 \, a^{3} \cos \left (d x + c\right )^{4} + 3 \, a^{3} \cos \left (d x + c\right )^{3} - a^{3} \cos \left (d x + c\right )^{2}\right )} \log \left (-\cos \left (d x + c\right )\right ) + 3 \, {\left (a^{3} \cos \left (d x + c\right )^{5} - 3 \, a^{3} \cos \left (d x + c\right )^{4} + 3 \, a^{3} \cos \left (d x + c\right )^{3} - a^{3} \cos \left (d x + c\right )^{2}\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) + 333 \, {\left (a^{3} \cos \left (d x + c\right )^{5} - 3 \, a^{3} \cos \left (d x + c\right )^{4} + 3 \, a^{3} \cos \left (d x + c\right )^{3} - a^{3} \cos \left (d x + c\right )^{2}\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right )}{48 \, {\left (d \cos \left (d x + c\right )^{5} - 3 \, d \cos \left (d x + c\right )^{4} + 3 \, d \cos \left (d x + c\right )^{3} - d \cos \left (d x + c\right )^{2}\right )}} \]

input
integrate(csc(d*x+c)^7*(a+a*sec(d*x+c))^3,x, algorithm="fricas")
 
output
1/48*(330*a^3*cos(d*x + c)^4 - 822*a^3*cos(d*x + c)^3 + 596*a^3*cos(d*x + 
c)^2 - 72*a^3*cos(d*x + c) - 24*a^3 - 336*(a^3*cos(d*x + c)^5 - 3*a^3*cos( 
d*x + c)^4 + 3*a^3*cos(d*x + c)^3 - a^3*cos(d*x + c)^2)*log(-cos(d*x + c)) 
 + 3*(a^3*cos(d*x + c)^5 - 3*a^3*cos(d*x + c)^4 + 3*a^3*cos(d*x + c)^3 - a 
^3*cos(d*x + c)^2)*log(1/2*cos(d*x + c) + 1/2) + 333*(a^3*cos(d*x + c)^5 - 
 3*a^3*cos(d*x + c)^4 + 3*a^3*cos(d*x + c)^3 - a^3*cos(d*x + c)^2)*log(-1/ 
2*cos(d*x + c) + 1/2))/(d*cos(d*x + c)^5 - 3*d*cos(d*x + c)^4 + 3*d*cos(d* 
x + c)^3 - d*cos(d*x + c)^2)
 
3.1.46.6 Sympy [F(-1)]

Timed out. \[ \int \csc ^7(c+d x) (a+a \sec (c+d x))^3 \, dx=\text {Timed out} \]

input
integrate(csc(d*x+c)**7*(a+a*sec(d*x+c))**3,x)
 
output
Timed out
 
3.1.46.7 Maxima [A] (verification not implemented)

Time = 0.20 (sec) , antiderivative size = 145, normalized size of antiderivative = 0.92 \[ \int \csc ^7(c+d x) (a+a \sec (c+d x))^3 \, dx=\frac {3 \, a^{3} \log \left (\cos \left (d x + c\right ) + 1\right ) + 333 \, a^{3} \log \left (\cos \left (d x + c\right ) - 1\right ) - 336 \, a^{3} \log \left (\cos \left (d x + c\right )\right ) + \frac {2 \, {\left (165 \, a^{3} \cos \left (d x + c\right )^{4} - 411 \, a^{3} \cos \left (d x + c\right )^{3} + 298 \, a^{3} \cos \left (d x + c\right )^{2} - 36 \, a^{3} \cos \left (d x + c\right ) - 12 \, a^{3}\right )}}{\cos \left (d x + c\right )^{5} - 3 \, \cos \left (d x + c\right )^{4} + 3 \, \cos \left (d x + c\right )^{3} - \cos \left (d x + c\right )^{2}}}{48 \, d} \]

input
integrate(csc(d*x+c)^7*(a+a*sec(d*x+c))^3,x, algorithm="maxima")
 
output
1/48*(3*a^3*log(cos(d*x + c) + 1) + 333*a^3*log(cos(d*x + c) - 1) - 336*a^ 
3*log(cos(d*x + c)) + 2*(165*a^3*cos(d*x + c)^4 - 411*a^3*cos(d*x + c)^3 + 
 298*a^3*cos(d*x + c)^2 - 36*a^3*cos(d*x + c) - 12*a^3)/(cos(d*x + c)^5 - 
3*cos(d*x + c)^4 + 3*cos(d*x + c)^3 - cos(d*x + c)^2))/d
 
3.1.46.8 Giac [A] (verification not implemented)

Time = 0.40 (sec) , antiderivative size = 243, normalized size of antiderivative = 1.55 \[ \int \csc ^7(c+d x) (a+a \sec (c+d x))^3 \, dx=\frac {666 \, a^{3} \log \left (\frac {{\left | -\cos \left (d x + c\right ) + 1 \right |}}{{\left | \cos \left (d x + c\right ) + 1 \right |}}\right ) - 672 \, a^{3} \log \left ({\left | -\frac {\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1} - 1 \right |}\right ) + \frac {{\left (2 \, a^{3} - \frac {27 \, a^{3} {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} + \frac {234 \, a^{3} {\left (\cos \left (d x + c\right ) - 1\right )}^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} - \frac {1221 \, a^{3} {\left (\cos \left (d x + c\right ) - 1\right )}^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}}\right )} {\left (\cos \left (d x + c\right ) + 1\right )}^{3}}{{\left (\cos \left (d x + c\right ) - 1\right )}^{3}} + \frac {48 \, {\left (33 \, a^{3} + \frac {50 \, a^{3} {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} + \frac {21 \, a^{3} {\left (\cos \left (d x + c\right ) - 1\right )}^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}\right )}}{{\left (\frac {\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1} + 1\right )}^{2}}}{96 \, d} \]

input
integrate(csc(d*x+c)^7*(a+a*sec(d*x+c))^3,x, algorithm="giac")
 
output
1/96*(666*a^3*log(abs(-cos(d*x + c) + 1)/abs(cos(d*x + c) + 1)) - 672*a^3* 
log(abs(-(cos(d*x + c) - 1)/(cos(d*x + c) + 1) - 1)) + (2*a^3 - 27*a^3*(co 
s(d*x + c) - 1)/(cos(d*x + c) + 1) + 234*a^3*(cos(d*x + c) - 1)^2/(cos(d*x 
 + c) + 1)^2 - 1221*a^3*(cos(d*x + c) - 1)^3/(cos(d*x + c) + 1)^3)*(cos(d* 
x + c) + 1)^3/(cos(d*x + c) - 1)^3 + 48*(33*a^3 + 50*a^3*(cos(d*x + c) - 1 
)/(cos(d*x + c) + 1) + 21*a^3*(cos(d*x + c) - 1)^2/(cos(d*x + c) + 1)^2)/( 
(cos(d*x + c) - 1)/(cos(d*x + c) + 1) + 1)^2)/d
 
3.1.46.9 Mupad [B] (verification not implemented)

Time = 13.29 (sec) , antiderivative size = 151, normalized size of antiderivative = 0.96 \[ \int \csc ^7(c+d x) (a+a \sec (c+d x))^3 \, dx=\frac {111\,a^3\,\ln \left (\cos \left (c+d\,x\right )-1\right )}{16\,d}+\frac {a^3\,\ln \left (\cos \left (c+d\,x\right )+1\right )}{16\,d}+\frac {-\frac {55\,a^3\,{\cos \left (c+d\,x\right )}^4}{8}+\frac {137\,a^3\,{\cos \left (c+d\,x\right )}^3}{8}-\frac {149\,a^3\,{\cos \left (c+d\,x\right )}^2}{12}+\frac {3\,a^3\,\cos \left (c+d\,x\right )}{2}+\frac {a^3}{2}}{d\,\left (-{\cos \left (c+d\,x\right )}^5+3\,{\cos \left (c+d\,x\right )}^4-3\,{\cos \left (c+d\,x\right )}^3+{\cos \left (c+d\,x\right )}^2\right )}-\frac {7\,a^3\,\ln \left (\cos \left (c+d\,x\right )\right )}{d} \]

input
int((a + a/cos(c + d*x))^3/sin(c + d*x)^7,x)
 
output
(111*a^3*log(cos(c + d*x) - 1))/(16*d) + (a^3*log(cos(c + d*x) + 1))/(16*d 
) + ((3*a^3*cos(c + d*x))/2 + a^3/2 - (149*a^3*cos(c + d*x)^2)/12 + (137*a 
^3*cos(c + d*x)^3)/8 - (55*a^3*cos(c + d*x)^4)/8)/(d*(cos(c + d*x)^2 - 3*c 
os(c + d*x)^3 + 3*cos(c + d*x)^4 - cos(c + d*x)^5)) - (7*a^3*log(cos(c + d 
*x)))/d